Question

1. if a colorblind son from the previous problem has children with a woman with normal color vision (homozygous dominant). what percentage of the sons is colorblind? make a punnett square to find out.
2. what would be one of the possible sets of parental genotypes that produce a colorblind daughter?

Explanation:

Step1: Determine genotypes

Color - blindness is X - linked recessive. Let $X^B$ be the normal allele and $X^b$ be the color - blind allele. A color - blind son has genotype $X^bY$. A homozygous dominant woman has genotype $X^BX^B$.

Step2: Create Punnett square

	$X^B$	$X^B$
$Y$	$X^BY$	$X^BY$

Step3: Analyze sons' genotypes

The genotypes of sons are $X^BY$. None of the sons are color - blind.

For question 8:
A color - blind daughter has genotype $X^bX^b$. One possible set of parental genotypes is a color - blind father ($X^bY$) and a carrier mother ($X^BX^b$).

Answer:

1. 0%
2. Father: $X^bY$, Mother: $X^BX^b$