Question

date:4) the female dog has black fur. the male dog has black fur. figure out the phenotypes and genotypes of their possible puppies by using a punnett square.% of possible genotypes:ff: _____ff: ___ff: ___% of possible phenotypes:black fur: _____grey fur: _____5) the female dog is heterozygous. the male dog is heterozygous. figure out the phenotypes and genotypes of their possible puppies by using a punnett square.% of possible genotypes:ff: ___ff: ___ff: ___% of possible phenotypes:black fur: _____grey fur: _______6) in fruit flies, red eyes are dominant (e). white eyes are recessive (e). if the female fly has white eyes and the male fly has homozygous dominant red eyes, what are the possible phenotypes and genotypes of their offspring?genotypes:ee:ee:ee:phenotypes:red eyes:white eyes:

Explanation:

Problem 4

Step1: Define allele dominance

Black fur (F) is dominant; grey fur (f) is recessive. Since both parents have black fur, we assume they are homozygous dominant (FF) (the most basic case for black fur without additional info).

Step2: Set up Punnett Square

Female gametes: F, F; Male gametes: F, F

$$\begin{array}{c|cc} & F & F \\ \hline F & FF & FF \\ F & FF & FF \\ \end{array}$$

Step3: Calculate genotype percentages

Count each genotype: All 4 squares are FF.
FF: $\frac{4}{4} \times 100\% = 100\%$; Ff: $0\%$; ff: $0\%$

Step4: Calculate phenotype percentages

All puppies have FF, so all show dominant black fur.
Black fur: $100\%$; Grey fur: $0\%$

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Problem 5

Step1: Identify parent genotypes

Both parents are heterozygous: Ff (black fur, since dominant F is expressed).

Step2: Set up Punnett Square

Female gametes: F, f; Male gametes: F, f

$$\begin{array}{c|cc} & F & f \\ \hline F & FF & Ff \\ f & Ff & ff \\ \end{array}$$

Step3: Calculate genotype percentages

FF: $\frac{1}{4} \times 100\% = 25\%$; Ff: $\frac{2}{4} \times 100\% = 50\%$; ff: $\frac{1}{4} \times 100\% = 25\%$

Step4: Calculate phenotype percentages

Black fur (FF + Ff): $\frac{3}{4} \times 100\% = 75\%$; Grey fur (ff): $\frac{1}{4} \times 100\% = 25\%$

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Problem 6

Step1: Identify parent genotypes

Female fly (white eyes, recessive): ee; Male fly (homozygous dominant red eyes): EE.

Step2: Set up Punnett Square

Female gametes: e, e; Male gametes: E, E

$$\begin{array}{c|cc} & E & E \\ \hline e & Ee & Ee \\ e & Ee & Ee \\ \end{array}$$

Step3: Calculate genotype percentages

EE: $0\%$; Ee: $\frac{4}{4} \times 100\% = 100\%$; ee: $0\%$

Step4: Calculate phenotype percentages

All offspring have Ee, so all show dominant red eyes.
Red Eyes: $100\%$; White Eyes: $0\%$

Answer:

Problem 4

% of possible Genotypes:
FF: 100%
Ff: 0%
ff: 0%
% of possible Phenotypes:
Black fur: 100%
Grey fur: 0%
Punnett Square:

$$\begin{array}{c|cc} & F & F \\ \hline F & FF & FF \\ F & FF & FF \\ \end{array}$$

Problem 5

% of possible Genotypes:
FF: 25%
Ff: 50%
ff: 25%
% of possible Phenotypes:
Black fur: 75%
Grey fur: 25%
Punnett Square:

$$\begin{array}{c|cc} & F & f \\ \hline F & FF & Ff \\ f & Ff & ff \\ \end{array}$$

Problem 6

Genotypes:
EE: 0%
Ee: 100%
ee: 0%
Phenotypes:
Red Eyes: 100%
White Eyes: 0%