Question

date

1. make a punnett square for a cross between two dog parents with semi - floppy ears (ee). fill in the genotypes and phenotypes for all the possible offspring. (tip: see question 5 for more information about these alleles)

f. calculating probability
dominant, recessive, and co - dominant traits follow predictable inheritance patterns. you can use a punnett square to predict the chances (or probability) of offspring having each possible genotype and phenotype.
example
this punnett square has 4 squares, which together represent all the possible genotypes for offspring from this cross. so for each possibility, the probability is ¼, or 25%. together, the possibilities add up to 1 (¼ + ¼ + ¼ + ¼), or 100% (25% + 25% + 25% + 25%).
in the punnett square above, two squares have a tt genotype, which make phenotype. to calculate the probability of this combination, you can add the values of the together.
probability of tall phenotype (tt)
25% + 25% = 50% (or) ¼ + ¼ = ½
you can do the same for the short phenotype (tt):
25% + 25% = 50% (or) ¼ + ¼ = ½
these calculations tell us that of offspring from this mating, there is a 50% (or 1 in 2) chance that it will be tall, and a 50% (or 1 in 2) chance that it will be short.

Explanation:

Answer:

1. Punnett Square for $E^h e^h \times E^h e^h$:

	$E^h$	$e^h$
$e^h$	$E^h e^h$	$e^h e^h$

Genotypes: $25\% E^h E^h$, $50\% E^h e^h$, $25\% e^h e^h$