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in a dihybrid cross for round and yellow seeds (rryy x rryy), what is t…

Question

in a dihybrid cross for round and yellow seeds (rryy x rryy), what is the probability of having green and wrinkled seeds? key: r = round r = wrinkled y = yellow y = green 1:16 3:16 8:16 9:16

Explanation:

Step1: Determine allele - combinations for parents

Each parent (RrYy) can produce 4 types of gametes: RY, Ry, rY, ry.

Step2: Use Punnett - square analysis

A dihybrid cross between RrYy and RrYy results in a 4x4 Punnett - square with 16 possible offspring combinations.

Step3: Identify genotype for green and wrinkled seeds

The genotype for green and wrinkled seeds is rryy.

Step4: Count the number of rryy offspring

There is 1 rryy combination out of 16 possible combinations in the Punnett - square.

Answer:

1:16