Question

dna and rna
a gene on a strand of dna has the following nucleotide sequence
ccc - aag - tgg
part a
what are the mrna triplets coded for from this gene?
a ggg uuc acc
b ccc aag tgg
c ggg ttc acc
d uuu ccc aga
part b
what is the sequence of amino acids formed from this gene?
a glycine - leucine - serine
b valine - glycine - arginine
c valine - lysine - tryptophan
d glycine - phenylalanine - threonine

Explanation:

Step1: Transcribe DNA to mRNA

DNA: CCC - AAG - TGG. In transcription, C pairs with G, A pairs with U (in RNA instead of T as in DNA), and G pairs with C. So the mRNA sequence is GGG - UUC - ACC.

Step2: Use the codon - table to find amino - acids

Using the provided codon - table:

• GGG codes for Glycine.
• UUC codes for Phenylalanine.
• ACC codes for Threonine.

Answer:

PART A: D. GGG UUC ACC
PART B: D. Glycine - Phenylalanine - Threonine