Question

dna: tac ggc ata
what is the rna sequence?
○ uac ggc aua
○ aug ggc uau
○ uag ccg uau
○ aug ccg uau

question 7
dna: gta tcc gaa
what is the rna sequence?
○ gua ucc gaa
○ cau agg cuu
○ cau ugg cuu
○ gau agg cuu

Explanation:

First Question (DNA: TAC GGC ATA)

Step1: Recall base pairing rules

In transcription, DNA to RNA: A (adenine) pairs with U (uracil), T (thymine) pairs with A (adenine), C (cytosine) pairs with G (guanine), G (guanine) pairs with C (cytosine).

Step2: Transcribe each DNA codon

• TAC: T→A, A→U, C→G → AUG
• GGC: G→C, G→C, C→G → CCG? Wait, no, wait: Wait, DNA is TAC GGC ATA. Let's do each nucleotide:

First codon: T (DNA) → A (RNA), A (DNA) → U (RNA), C (DNA) → G (RNA) → AUG
Second codon: G (DNA) → C (RNA)? No, wait, G (DNA) pairs with C (RNA)? Wait no, DNA to RNA: A-U, T-A, C-G, G-C. Wait, no: DNA has T, A, C, G. RNA has U, A, G, C. So:
T (DNA) → A (RNA)
A (DNA) → U (RNA)
C (DNA) → G (RNA)
G (DNA) → C (RNA)
So let's process each part:
DNA: T A C | G G C | A T A
Transcribe each:
T→A, A→U, C→G → A U G
G→C? Wait no, G (DNA) pairs with C (RNA)? Wait no, G (DNA) and C (RNA) are complementary? Wait, no: in DNA, G pairs with C. In RNA transcription, DNA's G is paired with C in RNA? Wait, no, the base pairing for transcription (DNA to mRNA) is: A (DNA) → U (RNA), T (DNA) → A (RNA), C (DNA) → G (RNA), G (DNA) → C (RNA). Wait, no, that's not right. Wait, the correct base pairing is: A (adenine) in DNA pairs with U (uracil) in RNA; T (thymine) in DNA pairs with A (adenine) in RNA; C (cytosine) in DNA pairs with G (guanine) in RNA; G (guanine) in DNA pairs with C (cytosine) in RNA. Wait, no, that's the reverse. Wait, no: the template DNA strand is used, and the RNA is synthesized by adding complementary nucleotides. So if DNA has a nucleotide, the RNA adds the complementary:

So DNA nucleotide: T → RNA: A (because T and A are complementary in DNA, but in RNA, instead of T, we use U, but the pairing is T (DNA) → A (RNA), A (DNA) → U (RNA), C (DNA) → G (RNA), G (DNA) → C (RNA). Wait, let's take an example: DNA sequence TAC. So T (DNA) → A (RNA), A (DNA) → U (RNA), C (DNA) → G (RNA) → AUG. Then GGC: G (DNA) → C (RNA)? No, G (DNA) and C (RNA) – wait, no, G (DNA) pairs with C (RNA)? Wait, no, G (DNA) and C (RNA) are complementary? Wait, no, G and C are complementary in DNA (G-C), so in RNA, when transcribing from DNA, G (DNA) will pair with C (RNA)? Wait, no, the RNA nucleotide that pairs with G (DNA) is C (RNA)? Wait, no, that's not correct. Wait, the correct pairing is:

DNA base: A → RNA base: U

DNA base: T → RNA base: A

DNA base: C → RNA base: G

DNA base: G → RNA base: C

Yes, that's correct. So:

For DNA sequence TAC GGC ATA:

First codon: TAC

T (DNA) → A (RNA)

A (DNA) → U (RNA)

C (DNA) → G (RNA) → AUG

Second codon: GGC

G (DNA) → C (RNA)

G (DNA) → C (RNA)

C (DNA) → G (RNA) → CCG? Wait, no, that can't be. Wait, the options are:

Options:

1. UAC GGC AUA

1. AUG GGC UAU

1. UAG CCG UAU

1. AUG CCG UAU

Wait, let's re-express the DNA: TAC GGC ATA

Break into nucleotides:

T (1st), A (2nd), C (3rd) | G (4th), G (5th), C (6th) | A (7th), T (8th), A (9th)

Transcribe each:

1. T → A

1. A → U

1. C → G → AUG (first codon)

1. G → C? No, wait, G (DNA) → C (RNA)? Wait, no, G (DNA) pairs with C (RNA)? Wait, no, the correct pairing is G (DNA) → C (RNA)? Wait, no, I think I made a mistake. Wait, DNA to RNA: A-U, T-A, C-G, G-C. Wait, no: C (DNA) pairs with G (RNA), G (DNA) pairs with C (RNA). Yes. So:

1. G (DNA) → C (RNA)

1. G (DNA) → C (RNA)

1. C (DNA) → G (RNA) → CCG? But the options have AUG CCG UAU as option 4. Let's check the third codon: ATA

1. A (DNA) → U (RNA)

1. T (DNA) → A (RNA)

1. A (DNA) → U (RNA) → UAU? Wait, no: ATA: A→U, T→A, A→U → UAU? Wait, no: A (DNA) → U (RNA), T (DNA) → A (RNA), A (DNA) → U (RNA) → UAU? Wait, but the third codon in DNA is ATA. So:

A (DNA…

Step1: Recall base pairing rules

Same as before: A-U, T-A, C-G, G-C.

Step2: Transcribe each DNA codon

DNA: GTA TCC GAA

Break into nucleotides: G (1), T (2), A (3) | T (4), C (5), C (6) | G (7), A (8), A (9)

Transcribe each:

1. G → C? No, G (DNA) → C (RNA)? Wait, no, G (DNA) pairs with C (RNA)? Wait, no, C (DNA) pairs with G (RNA), G (DNA) pairs with C (RNA). Wait, no, I think I had it reversed. Wait, no: DNA has C and G, RNA has G and C. So C (DNA) → G (RNA), G (DNA) → C (RNA). Yes. So:

1. G (DNA) → C (RNA)

1. T (DNA) → A (RNA)

1. A (DNA) → U (RNA) → CAU (first codon)

1. T (DNA) → A (RNA)

1. C (DNA) → G (RNA)

1. C (DNA) → G (RNA) → AGG (second codon)

1. G (DNA) → C (RNA)? No, G (DNA) → C (RNA)? Wait, no, G (DNA) → C (RNA)? Wait, no, G (DNA) pairs with C (RNA). So:

1. G (DNA) → C (RNA)

1. A (DNA) → U (RNA)

1. A (DNA) → U (RNA) → CUU (third codon)

Wait, let's do each codon:

First codon: GTA

G→C, T→A, A→U → CAU

Second codon: TCC

T→A, C→G, C→G → AGG

Third codon: GAA

G→C, A→U, A→U → CUU

So the RNA sequence is CAU AGG CUU, which is option 2.

Answer:

s:
First Question: D. AUG CCG UAU

Question 7: B. CAU AGG CUU