Question

due to random chromosome segregation, parent guinea pigs possess the alleles shown in the punnett square where b is a dominant allele for black coat.
what is the probability that the offspring of this cross will have a white coat?
a 0%
b 25%
c 50%
d 100%

Explanation:

Step1: Analyze Punnett - square

The Punnett - square shows a cross between parents with genotypes Bb and Bb. B is dominant for black coat and b is recessive for white coat.

Step2: Determine genotypes of offspring

The possible genotypes of the offspring from the cross Bb × Bb are BB:Bb:bb in the ratio 1:2:1.

Step3: Calculate probability of white - coat

Since white coat is determined by the recessive genotype bb, and the proportion of bb in the offspring is 1 out of 4. The probability is $\frac{1}{4}= 25\%$.

Answer:

B. 25%