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how can the shaded area below be calculated? (select all that apply) sh…

Question

how can the shaded area below be calculated? (select all that apply) show your work here

Explanation:

Step1: Analyze each circle's shaded fraction

Each circle is divided into 6 equal parts, and the shaded parts in each circle: Let's see, the first three circles (top row) and the last two (bottom row). Wait, actually, looking at the sectors: each circle has a white sector of \( \frac{1}{6} \)? Wait no, wait the white part: let's count the shaded regions. Wait, maybe each circle has \( \frac{5}{6} \) shaded? Wait no, looking at the diagram: each circle has a white triangle - shaped sector? Wait, no, the circles are divided into 6 equal sectors? Wait, no, maybe 6 sectors? Wait, the first circle: shaded sectors: let's count. Wait, maybe each circle has \( \frac{5}{6} \) shaded? Wait, no, let's check the number of circles. There are 5 circles? Wait, top row: 3 circles, bottom row: 2 circles. Total 5 circles. Each circle: let's see the shaded area. Let's assume each circle is a unit circle (area \( A \) per circle). Wait, maybe each circle has \( \frac{5}{6} \) of its area shaded? Wait, no, looking at the diagram: each circle has a white sector that is \( \frac{1}{6} \)? Wait, no, maybe the white part is \( \frac{1}{6} \), so shaded is \( 1 - \frac{1}{6}=\frac{5}{6} \) per circle. Then total shaded area would be number of circles times shaded fraction per circle. Wait, number of circles: 5? Wait, top row: 3, bottom row: 2. So 5 circles. So total shaded area: \( 5\times\frac{5}{6}=\frac{25}{6} \)? Wait, no, maybe I miscounted. Wait, let's re - examine:

Wait, maybe each circle has 5 shaded sectors out of 6. So per circle, shaded fraction is \( \frac{5}{6} \). Number of circles: 5. So total shaded area: \( 5\times\frac{5}{6}=\frac{25}{6} \), or alternatively, sum the shaded fractions. Another way: if we consider each circle's shaded area as \( \frac{5}{6} \), then for 5 circles, it's \( 5\times\frac{5}{6} \), or we can think of it as \( 3\times\frac{5}{6}+2\times\frac{5}{6}=(3 + 2)\times\frac{5}{6}=5\times\frac{5}{6} \).

Alternatively, maybe the white sector is \( \frac{1}{6} \), so shaded is \( \frac{5}{6} \) per circle. So total shaded area: number of circles \( \times\frac{5}{6} \). Since there are 5 circles, total shaded area is \( 5\times\frac{5}{6}=\frac{25}{6} \), or \( 4\frac{1}{6} \).

Wait, maybe the problem is about calculating the total shaded area of 5 circles, each with \( \frac{5}{6} \) shaded. So the methods to calculate:

  1. Multiply the number of circles (5) by the shaded fraction per circle (\( \frac{5}{6} \)): \( 5\times\frac{5}{6} \).
  1. Sum the shaded fractions: \( \frac{5}{6}+\frac{5}{6}+\frac{5}{6}+\frac{5}{6}+\frac{5}{6}=5\times\frac{5}{6} \) (using repeated addition, which is multiplication).

So the ways to calculate the shaded area are:

  • Multiply the number of circles (5) by the shaded fraction per circle (\( \frac{5}{6} \)): \( 5\times\frac{5}{6} \).
  • Add the shaded fraction (\( \frac{5}{6} \)) five times: \( \frac{5}{6}+\frac{5}{6}+\frac{5}{6}+\frac{5}{6}+\frac{5}{6} \), which is equivalent to \( 5\times\frac{5}{6} \) by the definition of multiplication (repeated addition).

Answer:

If we assume each circle has a shaded fraction of \( \frac{5}{6} \) and there are 5 circles, the shaded area can be calculated as \( 5\times\frac{5}{6}=\frac{25}{6} \) (or \( 4\frac{1}{6} \)) by multiplying the number of circles by the shaded fraction per circle, or by adding \( \frac{5}{6} \) five times.