Question

in humans, the gene for curly hair (h) is incompletely dominant to the gene for straight hair (h). individuals that are heterozygous (hh) have wavy hair. two wavy - haired heterozygous parents have a child. what is the likeliness that the child will have wavy hair? choose 1 answer: a (\frac{1}{4}) b (\frac{1}{2}) c (\frac{3}{4}) d (\frac{4}{4})

Explanation:

Step1: Determine Parental Genotypes

Both parents are heterozygous (Hh) for wavy hair.

Step2: Create Punnett Square

The possible gametes from each parent are H and h. The Punnett square is:

	H	h
h	Hh	hh

Step3: Analyze Offspring Genotypes

The offspring genotypes are HH (curly), Hh (wavy), Hh (wavy), hh (straight).

Step4: Calculate Probability for Wavy Hair

There are 2 out of 4 (or $\frac{2}{4}=\frac{1}{2}$) offspring with Hh (wavy hair).

Answer:

B. $\frac{1}{2}$