Question

identify the reaction that occurs when the base koh is added to the buffer solution. drag each label to the appropriate target. view available hint(s) reset help hf(aq) + kbr(aq) h₂o(l) + kf(aq) hf(aq) + kf(aq) koh(aq) + hf(aq) h₂o(l) + kbr(aq) kf(aq) + koh(aq) buffer solution hf(aq) kf(aq) add koh:

Explanation:

Step1: Identify the reactants

The buffer solution contains \( \text{HF}(aq) \) and \( \text{KF}(aq) \), and we are adding \( \text{KOH}(aq) \). The base \( \text{KOH} \) will react with the acid \( \text{HF} \) in the buffer. So the reaction between the added \( \text{KOH} \) and the acid in the buffer is \( \text{KOH}(aq) + \text{HF}(aq) \).

Step2: Determine the products

When a strong base (\( \text{KOH} \)) reacts with a weak acid (\( \text{HF} \)), the products are water and the salt formed from the cation of the base and the anion of the acid. The reaction is a neutralization reaction: \( \text{KOH}(aq) + \text{HF}(aq)
ightarrow \text{H}_2\text{O}(l) + \text{KF}(aq) \). So the reactant side (before reaction) is \( \text{KOH}(aq) + \text{HF}(aq) \) and the product side (after reaction) is \( \text{H}_2\text{O}(l) + \text{KF}(aq) \).

Answer:

First box (reactant): \( \text{KOH}(aq) + \text{HF}(aq) \)
Second box (product): \( \text{H}_2\text{O}(l) + \text{KF}(aq) \)