Question

to be metabolized, glucose must be converted to glucose 6 - phosphate. however, the phosphorylation of glucose to form glucose 6 - phosphate is endergonic with a positive δg. how do cells circumvent this problem? the reaction is coupled to the hydrolysis of atp, making the entire process exergonic. the reaction is catalyzed by an enzyme, which allows the reaction to proceed by lowering its activation energy. the reaction is catalyzed by an enzyme, which allows the reaction to proceed by changing its δg. an enzyme changes the equilibrium constant for the reaction to favor glucose 6 - phosphate formation. an enzyme raises the activation energy barrier to favor glucose 6 - phosphate formation.

Explanation:

Enzymes lower activation energy but do not change $\Delta G$ or equilibrium constant. The endergonic phosphorylation of glucose is coupled with the exergonic hydrolysis of ATP to drive the reaction forward.

Answer:

The reaction is coupled to the hydrolysis of ATP, making the entire process exergonic.