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Question
multiple - choice question based on its name (=deoxyribose) and its class, the formula for deoxyribose is c₁₀h₂₀o₅ c₅h₁₀o₅ c₆h₁₂o₆
Step1: Recall deoxyribose properties
Deoxyribose is a pentose sugar, which means it has 5 carbon atoms.
Step2: Determine general sugar formula
The general formula for a monosaccharide is $C_nH_{2n}O_n$. For a pentose ($n = 5$), the formula is $C_5H_{10}O_5$. But deoxyribose has one less oxygen - it is 2 - deoxyribose. However, among the given options, the correct formula for a pentose - related structure is $C_5H_{10}O_5$ as it is the closest match considering the context.
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B. $C_5H_{10}O_5$