Question

name:
mad minute: vsepr shapes & angles
directions: fill in the missing information with diagrams, shapes, angles or bonding pair and lone pairs.

molecule diagram (include lone pairs)	# of bonding pairs and lone pairs on central atom	vsepr shape/geometry	vsepr angle

| diagram of a linear molecule | bonding pair: ____
lone pairs: ____ | | 180° |
| | bonding pair: 3
lone pairs: 0 | trigonal planar | 120° |
| diagram of a molecule with 2 bonding pairs and 1 lone pair | bonding pair: 2
lone pairs: 1 | | <120° |
| diagram of a tetrahedral molecule | bonding pair: ____
lone pairs: ____ | | 109.5° |
| diagram of a molecule with 3 bonding pairs and 1 lone pair | bonding pair: 3
lone pairs: 1 | | |
| | bonding pair: 2
lone pairs: 2 | | <109.5° |
© 2025 uncommon schools, inc. all rights reserved.
2

Answer:

First Row (Linear Molecule):

Step1: Analyze the molecule diagram

The first molecule diagram is a straight line with three atoms (two terminal, one central), so it's a linear structure. For a linear molecule, the central atom has 2 bonding pairs and 0 lone pairs (since there are no lone pairs shown, and the geometry is linear which corresponds to 2 bonding pairs and 0 lone pairs in VSEPR).
Bonding Pair: 2
Lone Pairs: 0
VSEPR Shape/Geometry: Linear

Second Row (Trigonal Planar):

The molecule diagram for trigonal planar (with 3 bonding pairs and 0 lone pairs) would be a central atom with three terminal atoms forming a triangle (planar) around it. So we can draw a central atom with three atoms attached, each at 120° to each other.

Third Row (Bent or V - shaped with 1 lone pair):

The molecule diagram has a central atom with two terminal atoms and one lone pair (represented by the two dots). The VSEPR shape here is bent (or angular) because of the 1 lone pair. So VSEPR Shape/Geometry: Bent (or Angular)

Fourth Row (Tetrahedral - like with 4 bonding pairs):

The molecule diagram has a central atom with four terminal atoms, which is a tetrahedral geometry. In tetrahedral, the central atom has 4 bonding pairs and 0 lone pairs (since all electron pairs are bonding, as there are no lone pairs shown).
Bonding Pair: 4
Lone Pairs: 0
VSEPR Shape/Geometry: Tetrahedral

Fifth Row (Trigonal Pyramidal):

The molecule diagram has a central atom with three terminal atoms and one lone pair (represented by the two dots). The VSEPR shape here is trigonal pyramidal (because of the 1 lone pair, the shape is a pyramid with a triangular base).
VSEPR Shape/Geometry: Trigonal Pyramidal
The VSEPR angle here is less than 109.5° (since lone pairs repel more than bonding pairs, compressing the angle between the bonding pairs).

Sixth Row (Bent or V - shaped with 2 lone pairs):

The molecule has 2 bonding pairs and 2 lone pairs. The VSEPR shape here is bent (or angular) with a tetrahedral electron - pair geometry but molecular geometry is bent. The molecule diagram would have a central atom with two terminal atoms and two lone pairs (represented by dots).
VSEPR Shape/Geometry: Bent (or Angular)

Now, filling in the table:

Molecule Diagram (include lone pairs)	# of bonding pairs and lone pairs on central atom	VSEPR Shape/Geometry	VSEPR Angle
<img src="https://via.placeholder.com/80x40?text=Trigonal+Planar" /> (trigonal planar, 3 bonding, 0 lone)	Bonding Pair: 3<br>Lone Pairs: 0	Trigonal planar	$120^{\circ}$
<img src="https://via.placeholder.com/50x30?text=Bent+1+Lone+Pair" /> (bent, 2 bonding, 1 lone)	Bonding Pair: 2<br>Lone Pairs: 1	Bent (Angular)	$<120^{\circ}$
<img src="https://via.placeholder.com/60x40?text=Tetrahedral" /> (tetrahedral, 4 bonding, 0 lone)	Bonding Pair: 4<br>Lone Pairs: 0	Tetrahedral	$109.5^{\circ}$
<img src="https://via.placeholder.com/50x30?text=Trigonal+Pyramidal" /> (trigonal pyramidal, 3 bonding, 1 lone)	Bonding Pair: 3<br>Lone Pairs: 1	Trigonal Pyramidal	$<109.5^{\circ}$
<img src="https://via.placeholder.com/50x30?text=Bent+2+Lone+Pairs" /> (bent, 2 bonding, 2 lone)	Bonding Pair: 2<br>Lone Pairs: 2	Bent (Angular)	$<109.5^{\circ}$

Final Table:

Molecule Diagram (include lone pairs)	# of bonding pairs and lone pairs on central atom	VSEPR Shape/Geometry	VSEPR Angle
<img src="https://via.placeholder.com/80x40?text=Trigonal+Planar" />	Bonding Pair: 3<br>Lone Pairs: 0	Trigonal planar	$120^{\circ}$
<img src="https://via.placeholder.com/50x30?text=Bent+1+Lone+Pair" />	Bonding Pair: 2<br>Lone Pairs: 1	Bent (Angular)	$<120^{\circ}$
<img src="https://via.placeholder.com/60x40?text=Tetrahedral" />	Bonding Pair: 4<br>Lone Pairs: 0	Tetrahedral	$109.5^{\circ}$
<img src="https://via.placeholder.com/50x30?text=Trigonal+Pyramidal" />	Bonding Pair: 3<br>Lone Pairs: 1	Trigonal Pyramidal	$<109.5^{\circ}$
<img src="https://via.placeholder.com/50x30?text=Bent+2+Lone+Pairs" />	Bonding Pair: 2<br>Lone Pairs: 2	Bent (Angular)	$<109.5^{\circ}$

If we are only focusing on filling the missing "Bonding Pair", "Lone Pairs" and "VSEPR Shape/Geometry" for each row:

1. First row:

• Bonding Pair: $\boldsymbol{2}$
• Lone Pairs: $\boldsymbol{0}$
• VSEPR Shape/Geometry: $\boldsymbol{Linear}$

1. Second row: (diagram should be a central atom with 3 atoms attached in a triangle)

1. Third row:

• VSEPR Shape/Geometry: $\boldsymbol{Bent\ (Angular)}$

1. Fourth row:

• Bonding Pair: $\boldsymbol{4}$
• Lone Pairs: $\boldsymbol{0}$
• VSEPR Shape/Geometry: $\boldsymbol{Tetrahedral}$

1. Fifth row:

• VSEPR Shape/Geometry: $\boldsymbol{Trigonal\ Pyramidal}$

1. Sixth row:

• VSEPR Shape/Geometry: $\boldsymbol{Bent\ (Angular)}$