Question

this passage describes the flower form trait in rose plants: roses may grow single flowers or double flowers. double flowers have more petals than single flowers and are highly prized by gardeners. however, these extra petals may block or replace parts of the flower needed for reproduction. this makes double - flowered plants difficult to breed. in a group of rose plants, some individuals have double flowers and others have single flowers. in this group, the gene for the flower form trait has two alleles. the allele for single flowers (f) is recessive to the allele for double flowers (f). this punnett square shows a cross between two rose plants. (punnett square with f, f on top; f, f on the side, and cells ff, ff, ff, ff) what is the probability that a rose plant produced by this cross will have single flowers? %

Explanation:

Step1: Identify single flower genotype

Single flowers require homozygous recessive genotype $ff$.

Step2: Count Punnett square outcomes

Total possible genotypes: $FF, FF, Ff, Ff$ (4 total). No $ff$ genotypes present.

Step3: Calculate probability

Probability = $\frac{\text{Number of } ff \text{ genotypes}}{\text{Total number of genotypes}} = \frac{0}{4}$

Step4: Convert to percentage

$0 \times 100\% = 0\%$

Answer:

$0\%$