Question

a pea plant that has round seeds has the genotype rr. it is crossed with a pea plant that has wrinkled seeds and the genotype rr. what is the probability that the offspring will have wrinkled seeds?
○ 0 percent
○ 25 percent
○ 50 percent
○ 75 percent

Explanation:

Step1: Identify parent gametes

Parent 1 (Rr) produces gametes: $R$, $r$
Parent 2 (rr) produces gametes: $r$, $r$

Step2: Create Punnett square

$$\begin{array}{c|cc} & R & r \\ \hline r & Rr & rr \\ r & Rr & rr \\ \end{array}$$

Step3: Calculate wrinkled seed probability

Wrinkled seeds require genotype $rr$. Count $rr$ outcomes: 2 out of 4 total.
Probability = $\frac{2}{4} = 0.5$ or 50%

Answer:

50 percent