Question

a pea plant that has round seeds has the genotype rr. it is crossed with a pea plant that has wrinkled seeds and the genotype rr. what is the probability that the offspring will have wrinkled seeds? 0 percent 25 percent 50 percent 75 percent

Explanation:

Step1: Set up the Punnett - square

The first parent has genotype Rr and can produce two types of gametes: R and r. The second parent has genotype rr and can produce only r gametes.

Step2: Fill in the Punnett - square

	R	r
r	Rr	rr

Step3: Determine the probability

Out of the 4 possible genotypes of the offspring, 2 are rr (wrinkled - seed genotype). The probability is $\frac{2}{4}=0.5$ or 50 percent.

Answer:

50 percent