Question

punnett square practice one: parent 1 black lab (li) parent 2: blonde lab (ll) punnett square practice two parent 1: red flower (rr) parent 2: white flower (rr) (these flowers blend when crossbred.) genotype: li: ll phenotype: % black % blonde genotype: rr phenotype: % red % white % pink

Explanation:

Step1: Fill Punnett - square for Lab dogs

The first Punnett - square has parents with genotypes LI and II. The possible combinations of alleles in offspring are:

	L	I
I	LI	II

So, the genotypes are 2 LI : 2 II.

Step2: Calculate phenotype percentages for Lab dogs

Since the dominant allele L gives black color and recessive allele I gives blonde color, and there are 2 LI (black) and 2 II (blonde) out of 4 total offspring. The percentage of black is $\frac{2}{4}\times100 = 50\%$ and the percentage of blonde is $\frac{2}{4}\times100 = 50\%$.

Step3: Fill Punnett - square for flowers

The second Punnett - square has parents with genotypes RR and rr. The possible combinations of alleles in offspring are:

	R	R
r	Rr	Rr

So, the genotype is 4 Rr.

Step4: Calculate phenotype percentages for flowers

Since these flowers blend when cross - bred, R represents red and r represents white, and Rr results in pink. The percentage of red is 0%, the percentage of white is 0%, and the percentage of pink is 100%.

Answer:

Genotype for Lab dogs: 2 LI : 2 II
Phenotype for Lab dogs: 50% Black, 50% Blonde
Genotype for flowers: 4 Rr
Phenotype for flowers: 0% Red, 0% White, 100% Pink