Question

question 9
in genetic cross 10. cystic fibrosis. if you crossed a carrier male with a female with cystic fibrosis, what percentage of the offspring would have cystic fibrosus.
enter answer

question 10
in the genetic cross 11 hemophilia. what is the phenotypic ratio if you crossed a male hemophiliac with a carrier female?
normal male enter answer : normal female enter answer : carrier female
enter answer : hemophiliac male enter answer : hemophiliac female
enter answer

Explanation:

Question 9

Step1: Define alleles

Let the normal allele be $A$ and the cystic - fibrosis allele be $a$. A carrier male has the genotype $Aa$ and a female with cystic fibrosis has the genotype $aa$.

Step2: Set up Punnett - square

The possible gametes from the male are $A$ and $a$, and from the female are all $a$. The Punnett - square has two rows (female gametes) and two columns (male gametes).

Step3: Determine genotypes of offspring

The genotypes of the offspring are $Aa$ and $aa$ in a 1:1 ratio.

Step4: Calculate percentage

Since half of the offspring have the genotype $aa$ (which has cystic fibrosis), the percentage is 50%.

Step1: Define alleles

Let the normal allele for blood - clotting be $H$ and the hemophilia allele be $h$. A male hemophiliac has the genotype $X^hY$ and a carrier female has the genotype $X^HX^h$.

Step2: Set up Punnett - square

The possible gametes from the male are $X^h$ and $Y$, and from the female are $X^H$ and $X^h$.

Step3: Determine genotypes of offspring

The genotypes of the offspring are $X^HX^h$ (carrier female), $X^hX^h$ (hemophiliac female), $X^HY$ (normal male), $X^hY$ (hemophiliac male) in a 1:1:1:1 ratio.

Answer:

50%

Question 10