Question

question 6
in the genetic cross 7 pea plant flower color. what is the phenotypic ratio if you crossed a homozygous purple flowered plant with a homozygous white flowered plant? purple enter answer : white
enter answer

question 7
in the genetic 7 pea plant flower color. what is the genotypic ratioif you crossed a homozygous purple flowered plant with a homozygous white flowered plant? homozygous purple enter answer : heterozygous
enter answer : homozygous white enter answer

question 8
in genetic cross 9. pea plant seed color. what is the probability that you will have a yellow seeded plant if you crossed two heterozygous plants
enter answer

Explanation:

Step1: Set up genotypes

Let \(P\) represent the dominant allele for purple flower color and \(p\) represent the recessive allele for white flower color. A homozygous purple - flowered plant has genotype \(PP\) and a homozygous white - flowered plant has genotype \(pp\).

Step2: Determine the F1 generation for Question 6

When \(PP\times pp\), all offspring in the F1 generation have the genotype \(Pp\). Since the presence of the dominant \(P\) allele results in purple flowers, the phenotypic ratio of purple : white is \(1:0\).

Step3: Determine the F1 generation for Question 7

When \(PP\times pp\), all offspring have the genotype \(Pp\). So the genotypic ratio of homozygous purple (\(PP\)) : heterozygous (\(Pp\)) : homozygous white (\(pp\)) is \(0:1:0\).

Step4: Set up genotypes for Question 8

Let \(Y\) represent the dominant allele for yellow seed color and \(y\) represent the recessive allele for green seed color. When two heterozygous plants (\(Yy\times Yy\)) are crossed, the Punnett - square analysis gives the genotypes \(YY:Yy:yy = 1:2:1\). The genotypes \(YY\) and \(Yy\) result in yellow - seeded plants. So the probability of having a yellow - seeded plant is \(\frac{3}{4}=0.75\).

Answer:

Question 6: \(1:0\)
Question 7: \(0:1:0\)
Question 8: \(0.75\)