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question 4 (5 points) sickle - cell anemia is an example of codominance…

Question

question 4 (5 points) sickle - cell anemia is an example of codominance. what implications does this have for people with one or two copies of the sickle - cell gene? a) people with two copies of the mutated gene have healthy red blood cells. people with one copy of the mutated gene dont have the disease but are carriers of the disease. b) people with two copies of the mutated gene have sickle - cell anemia. people with one copy of the mutated gene have healthy red blood cells. c) people with two copies of the mutated gene have sickle - cell anemia. people with one copy of the mutated gene have both healthy and misshapen hemoglobin and are carriers of the disease. d) people with two copies of the mutated gene are carriers of the disease. people with one copy of the mutated gene dont have the disease. question 5 (5 points) chargaffs rule states... a) in eukaryotes, the amount of g and t are equal, and the amount of a and c are equal, but not in prokaryotes. b) in humans, the amount of g and c are equal, and the amount of a and t are equal, but not in other species. c) in prokaryotes, the amount of c and t are equal, and the amount of a and g are equal, but not in eukaryotes. d) in any species, the amount of g and c are equal, and the amount of a and t are equal.

Explanation:

Brief Explanations

For Question 4: In codominance, both alleles are expressed. People with two copies of the sickle - cell mutated gene have sickle - cell anemia as both mutated alleles are expressed. People with one copy of the mutated gene have both healthy and misshapen hemoglobin and are carriers.
For Question 5: Chargaff's rule states that in any species, the amount of guanine (G) is equal to cytosine (C), and the amount of adenine (A) is equal to thymine (T).

Answer:

Question 4: C. People with two copies of the mutated gene have sickle - cell anemia. People with one copy of the mutated gene have both healthy and misshapen hemoglobin and are carriers of the disease.
Question 5: D. In any species, the amount of G and C are equal, and the amount of A and T are equal.