Question

for a random sample of 19 women, the average resting pulse rate is $\bar{x} = 76$ beats per minute, and the standard deviation is 4.3. what is the standard error of the sample mean?
a. 2.99
b. 2.72
c. 0.99
d. 4.24

Explanation:

Step1: Recall standard error formula

The standard error (SE) of the sample mean is calculated as $\text{SE} = \frac{s}{\sqrt{n}}$, where $s$ is the sample standard deviation, and $n$ is the sample size.

Step2: Identify given values

We have $s = 4.3$, $n = 19$.

Step3: Calculate denominator

Compute $\sqrt{n} = \sqrt{19} \approx 4.3589$

Step4: Compute standard error

$\text{SE} = \frac{4.3}{4.3589} \approx 0.99$

Answer:

c. 0.99