the reaction is: $2\ce{h_{2}o_{2}} \
ightarrow 2\ce{h_{2}o} + \ce{o_{2}}$
1. when the liver is added to the $\ce{h_{2}o_{2}}$, what gas is produced and released?
2. what test is done to prove this?
3. is this reaction endothermic or exothermic? explain your answer.
4. what is the liquid composed of that was poured off?
5. what happened when additional liver was added to the liquid that was poured off?
6. what happened when additional $\ce{h_{2}o_{2}}$ was added to the used liver?
7. explain the results documented in questions 5 and 6.
8. is the enzyme reusable and where is the enzyme (catalase) located- the liquid or the liver?

Question

Accepted Answer

### Question 1
# Brief Explanations:
The reaction given is $2\text{H}_2\text{O}_2
ightarrow 2\text{H}_2\text{O} + \text{O}_2$. Liver contains the enzyme catalase which speeds up the decomposition of hydrogen peroxide ($\text{H}_2\text{O}_2$). From the balanced chemical equation, the gas produced is oxygen ($\text{O}_2$).
# Answer:
Oxygen ($\text{O}_2$)

### Question 2
# Brief Explanations:
To test for the presence of oxygen gas, a glowing splint test is used. A glowing splint will relight when inserted into a gas that is oxygen because oxygen supports combustion.
# Answer:
Glowing splint test (a glowing splint will relight when placed in the gas, indicating the presence of oxygen)

### Question 3
# Brief Explanations:
The decomposition of hydrogen peroxide with liver (catalase) releases energy in the form of heat (you can feel the reaction mixture getting warmer). Exothermic reactions release energy (usually heat) into the surroundings, while endothermic reactions absorb energy. Since this reaction releases heat, it is exothermic.
# Answer:
Exothermic. The reaction releases heat (the mixture gets warmer), so energy is released into the surroundings, characteristic of an exothermic reaction.

### Question 4
# Brief Explanations:
The reaction is $2\text{H}_2\text{O}_2
ightarrow 2\text{H}_2\text{O} + \text{O}_2$. When the reaction occurs, the liquid poured off after the reaction (after the gas is released) is composed of water ($\text{H}_2\text{O}$) because the hydrogen peroxide decomposes into water and oxygen, and the oxygen is released as a gas, leaving water behind.
# Answer:
Water ($\text{H}_2\text{O}$)

### Question 5
# Brief Explanations:
The liquid poured off is water (from the decomposition of $\text{H}_2\text{O}_2$), which does not contain hydrogen peroxide anymore. The enzyme catalase in the liver acts on $\text{H}_2\text{O}_2$. Since there is no $\text{H}_2\text{O}_2$ in the poured - off liquid, adding more liver (which has catalase) will not cause a reaction (no gas production) because there is no substrate ($\text{H}_2\text{O}_2$) for the enzyme to act on.
# Answer:
No reaction (no gas bubbles are produced) because the liquid poured off is water (no $\text{H}_2\text{O}_2$ left) and the liver enzyme (catalase) needs $\text{H}_2\text{O}_2$ as a substrate to react.

### Question 6
# Brief Explanations:
The used liver still contains the enzyme catalase (enzymes are not used up in a reaction, they are reusable). When additional $\text{H}_2\text{O}_2$ is added to the used liver, the catalase in the liver will act on the new $\text{H}_2\text{O}_2$ and cause it to decompose, producing oxygen gas (so bubbles of oxygen will be seen).
# Answer:
Bubbles of gas (oxygen) are produced because the used liver still has the enzyme catalase which can catalyze the decomposition of the additional $\text{H}_2\text{O}_2$.

### Question 7
# Brief Explanations:
- For question 5: The liquid poured off was water (no $\text{H}_2\text{O}_2$ remaining). Enzymes (like catalase) need a substrate ($\text{H}_2\text{O}_2$ in this case) to catalyze a reaction. Since there was no substrate, adding liver (enzyme source) did not cause a reaction.
- For question 6: Enzymes are not consumed in a chemical reaction. The used liver still had the catalase enzyme. When additional $\text{H}_2\text{O}_2$ (substrate) was added, the catalase was able to catalyze the decomposition of $\text{H}_2\text{O}_2$ into water and oxygen, hence gas production occurred.
# Answer:
- In question 5: The liquid had no $\text{H}_2\text{O}_2$ (substrate), so the enzyme (from liver) had no substrate to act on, so no reaction.
- In question 6: Enzymes (catalase) are reusable; the used liver still had catalase, and with new $\text{H}_2\text{O}_2$ (substrate), the enzyme catalyzed $\text{H}_2\text{O}_2$ decomposition, producing gas.

### Question 8
# Brief Explanations:
Enzymes are reusable as they are not consumed in the chemical reaction (as seen in question 6, where used liver still catalyzed $\text{H}_2\text{O}_2$ decomposition). From question 5, adding liver to the poured - off liquid (water, no $\text{H}_2\text{O}_2$) had no reaction, and from question 6, adding $\text{H}_2\text{O}_2$ to used liver (with catalase) caused a reaction. This shows that the enzyme (catalase) is located in the liver (the solid part), not in the liquid (which was water from the reaction).
# Answer:
Yes, the enzyme (catalase) is reusable. The enzyme is located in the liver (not in the liquid) because adding liver to the liquid (no $\text{H}_2\text{O}_2$) didn't react, but adding $\text{H}_2\text{O}_2$ to used liver (with enzyme) did react.

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