Question

think about the process: the length of cell a is 3×10⁻⁵ m. the length of cell b is 0.000001 m. what is the ratio of cell as length to cell bs length? use pencil and paper. is it easier to find the ratio when the numbers are expressed in scientific notation or in standard form? explain your reasoning.
the ratio of cell as length to cell bs length is
(type the ratio as a simplified fraction.)

Explanation:

Step1: Write cell B's length in scientific - notation

The length of cell B is \(0.000001\ m = 1\times10^{-6}\ m\).

Step2: Calculate the ratio

The ratio of cell A's length to cell B's length is \(\frac{3\times 10^{-5}}{1\times 10^{-6}}\).
Using the rule of exponents \(\frac{a^m}{a^n}=a^{m - n}\), we have \(\frac{3\times 10^{-5}}{1\times 10^{-6}}=3\times10^{-5-(-6)} = 3\times10^{1}=30\). As a fraction, it is \(\frac{30}{1}\).

Answer:

\(\frac{30}{1}\)