Question

true breeding purple and white flowers make 100% purple flowers. what type of inheritance is this?
classic mendelian genetics (dominant/recessive)
incomplete dominance
codominance
polygenetic traits
question 5
1 pts
if black chickens and white chickens make speckled chickens, what would be the only wrong way to write the genotypes of the parents (so that you could not do a punnett square and get correct answers)
black = bb, white = ww, speckled = ss
black = bb, white = ww, speckled = bw
black = bb, white = bb, speckled = bb
black = cbcb, white = cwcw, speckled = cbcw
question 6
1 pts
blue butterflies and red butterflies make purple butterfly babies. cross a red butterfly with a blue butterfly. what are the phenotypes of the babies?
50% red, 50% blue
100% purple
25% red, 50% purple, 25% blue
cannot be determined

Explanation:

Question (First one: True breeding purple and white flowers...)

In classic Mendelian genetics (dominant/recessive), a dominant allele masks a recessive one. But here, true - breeding purple and white flowers producing 100% purple flowers would be classic Mendelian if purple is dominant. However, the option "Incomplete dominance" is wrong for this case, and "Classic Mendelian genetics (dominant/recessive)" is correct as in classic Mendelian, a dominant trait (purple, if dominant) from true - breeding parents (homozygous dominant purple and homozygous recessive white) would result in all offspring showing the dominant trait (purple).

In codominance, both alleles are expressed equally, and the genotype for the heterozygote (speckled) should show both alleles. Let's analyze each option:

• Option 1: Black = BB, White = WW, Speckled = SS. Here, the speckled genotype (SS) does not show the alleles from black (B) or white (W), so this is incorrect as it doesn't represent the combination of black and white alleles.
• Option 2: Black = BB, White = WW, Speckled = BW. This is a valid way to represent codominance (using different letters for different alleles).
• Option 3: Black = BB, White = bb, Speckled = Bb. This is a valid way (using the same letter with different cases, representing dominant and recessive, but in codominance, both are expressed, but this is still a way to write genotypes for a cross that gives a heterozygote).
• Option 4: Black = CBCB, White = CWCW, Speckled = CBCW. This is a valid way using codominant allele notation (showing both alleles in the heterozygote).

So the wrong way is the first option.

If blue and red make purple, and we cross a red (let's assume genotype RR) and a blue (genotype BB) butterfly. If the inheritance is such that the heterozygote (RB) is purple, and when we cross a red (RR) and blue (BB) butterfly, the Punnett square would give all offspring as RB (purple). Wait, but the options are about crossing a red and a blue butterfly. Wait, maybe there is a mis - statement, and it's a cross of two purple butterflies? No, the question says "Cross a red butterfly with a blue butterfly". Wait, if red (RR) and blue (BB) cross, the offspring would be RB (purple) 100%? But the options include 100% Purple. Let's check the options:

• 50% Red, 50% Blue: Incorrect, as the parents are red and blue, but the offspring are purple (from the initial statement that blue and red make purple babies).
• 100% Purple: If the cross of red and blue (homozygous for their respective colors) results in all purple (heterozygous, with both red and blue alleles expressed to make purple), then this is correct.
• 25% Red, 50% Purple, 25% Blue: This would be the case for a cross of two purple butterflies (Rr x Rr), not a red and blue.
• Cannot be determined: Incorrect, as we have the information that blue and red make purple babies.

So the answer is 100% Purple.

Answer:

Classic Mendelian genetics (dominant/recessive)

Question 5 (If black chickens and white chickens make speckled chickens...)