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from unit 2, lesson 13 in quadrilateral abcd, triangle adc is congruent…

Question

from unit 2, lesson 13 in quadrilateral abcd, triangle adc is congruent to triangle cba. show that quadrilateral abcd is a parallelogram.

Explanation:

Step1: Recall congruent - triangle properties

Since $\triangle ADC\cong\triangle CBA$, corresponding sides are equal. That is, $AD = CB$ and $DC=BA$.

Step2: Apply parallelogram definition

A quadrilateral is a parallelogram if both pairs of opposite sides are equal. In quadrilateral $ABCD$, we have $AD = CB$ and $DC = BA$. So, $ABCD$ is a parallelogram.

Answer:

Quadrilateral $ABCD$ is a parallelogram because when $\triangle ADC\cong\triangle CBA$, the opposite - sides of the quadrilateral ($AD$ and $CB$, $DC$ and $BA$) are equal, which satisfies the definition of a parallelogram.