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Question
from unit 2, lesson 13 in quadrilateral abcd, triangle adc is congruent to triangle cba. show that quadrilateral abcd is a parallelogram.
Step1: Recall congruent - triangle properties
Since $\triangle ADC\cong\triangle CBA$, corresponding sides are equal. That is, $AD = CB$ and $DC=BA$.
Step2: Apply parallelogram definition
A quadrilateral is a parallelogram if both pairs of opposite sides are equal. In quadrilateral $ABCD$, we have $AD = CB$ and $DC = BA$. So, $ABCD$ is a parallelogram.
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Quadrilateral $ABCD$ is a parallelogram because when $\triangle ADC\cong\triangle CBA$, the opposite - sides of the quadrilateral ($AD$ and $CB$, $DC$ and $BA$) are equal, which satisfies the definition of a parallelogram.