Question

using intercepts to graph transcript
using intercepts to graph by idla youtube, 01 may 2024, youtu.be/htth3ldewxk
equations | x - intercepts | choices
$2x + 3y = -12$ | | $(-6, 0)$
$-x - y = 1$ | | $(5, 0)$
$-8x - 10y = -40$ | | $(-5, 0)$
$-6x - 5y = 30$ | | $(-1, 0)$
alternative activity
equation | y - intercepts | choices

Explanation:

For the equation \(2x + 3y = -12\) to find the x - intercept:

Step 1: Recall the definition of x - intercept

The x - intercept is the point where \(y = 0\). So we substitute \(y = 0\) into the equation \(2x+3y=-12\).
\(2x + 3(0)=-12\)

Step 2: Solve for x

Simplify the equation: \(2x=-12\). Then divide both sides by 2: \(x=\frac{-12}{2}=-6\). So the x - intercept is \((-6,0)\).

For the equation \(-x - y = 1\) to find the x - intercept:

Step 1: Substitute \(y = 0\)

Substitute \(y = 0\) into \(-x - y = 1\), we get \(-x-0 = 1\).

Step 2: Solve for x

Simplify the equation: \(-x = 1\), then multiply both sides by - 1, we get \(x=-1\). So the x - intercept is \((-1,0)\).

For the equation \(-8x - 10y = -40\) to find the x - intercept:

Step 1: Substitute \(y = 0\)

Substitute \(y = 0\) into \(-8x-10y=-40\), we have \(-8x-10(0)=-40\).

Step 2: Solve for x

Simplify the equation: \(-8x=-40\). Divide both sides by - 8: \(x=\frac{-40}{-8} = 5\). So the x - intercept is \((5,0)\).

For the equation \(-6x - 5y = 30\) to find the x - intercept:

Answer:

s:

• For \(2x + 3y=-12\): \((-6,0)\)
• For \(-x - y = 1\): \((-1,0)\)
• For \(-8x - 10y=-40\): \((5,0)\)
• For \(-6x - 5y = 30\): \((-5,0)\)