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you make a punnett square for a cross and find the results shown below.…

Question

you make a punnett square for a cross and find the results shown below. female male your prediction is that of the offspring would have the dominant phenotype, and of the offspring would have the ssive phenotype. 25% 50% 75% 100%

Explanation:

Step1: Identify parental genotypes

Male: $X^x$ (heterozygous, $X$ = dominant, $x$ = recessive); Female: $X^x$ (heterozygous, $X$ = dominant, $x$ = recessive)

Step2: List all offspring genotypes

From Punnett square:

  1. $X^X$ (homozygous dominant)
  2. $X^x$ (heterozygous dominant)
  3. $X^x$ (heterozygous dominant)
  4. $x^x$ (homozygous recessive)

Step3: Calculate dominant phenotype %

Dominant genotypes: $X^X, X^x, X^x$ (3 out of 4)
$\text{Percentage} = \frac{3}{4} \times 100\% = 75\%$

Step4: Calculate recessive phenotype %

Recessive genotype: $x^x$ (1 out of 4)
$\text{Percentage} = \frac{1}{4} \times 100\% = 25\%$

Answer:

75% of the offspring would have the dominant phenotype, and 25% of the offspring would have the recessive phenotype.