Question

11 $y = 2x - 4$ (table with x and y values, graph) 6 $y = -x + 9$ (table with x: 1, 3, 5, 8; graph) 8 $y = -\frac{1}{4}x + 2$ (table with x: -8, -4, 0, 4; graph)

Explanation:

Problem 6: \( y = -x + 9 \)

Step1: Substitute \( x = 1 \)

Substitute \( x = 1 \) into \( y = -x + 9 \).
\( y = -1 + 9 = 8 \)

Step2: Substitute \( x = 3 \)

Substitute \( x = 3 \) into \( y = -x + 9 \).
\( y = -3 + 9 = 6 \)

Step3: Substitute \( x = 5 \)

Substitute \( x = 5 \) into \( y = -x + 9 \).
\( y = -5 + 9 = 4 \)

Step4: Substitute \( x = 8 \)

Substitute \( x = 8 \) into \( y = -x + 9 \).
\( y = -8 + 9 = 1 \)

Step1: Substitute \( x = -8 \)

Substitute \( x = -8 \) into \( y = -\frac{1}{4}x + 2 \).
\( y = -\frac{1}{4}(-8) + 2 = 2 + 2 = 4 \)

Step2: Substitute \( x = -4 \)

Substitute \( x = -4 \) into \( y = -\frac{1}{4}x + 2 \).
\( y = -\frac{1}{4}(-4) + 2 = 1 + 2 = 3 \)

Step3: Substitute \( x = 0 \)

Substitute \( x = 0 \) into \( y = -\frac{1}{4}x + 2 \).
\( y = -\frac{1}{4}(0) + 2 = 0 + 2 = 2 \)

Step4: Substitute \( x = 4 \)

Substitute \( x = 4 \) into \( y = -\frac{1}{4}x + 2 \).
\( y = -\frac{1}{4}(4) + 2 = -1 + 2 = 1 \)

Answer:

For \( x = 1 \), \( y = 8 \); for \( x = 3 \), \( y = 6 \); for \( x = 5 \), \( y = 4 \); for \( x = 8 \), \( y = 1 \).

Problem 8: \( y = -\frac{1}{4}x + 2 \)