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Question
y = -\frac{7}{2}x - 25\
\
| x | y | \ |
| -10 | \square | \ |
| -8 | \square | \ |
| -6 | \square |
Step1: Substitute \( x = -10 \) into the equation
We have the equation \( y = -\frac{7}{2}x - 25 \). Substitute \( x = -10 \) into it:
\( y = -\frac{7}{2} \times (-10) - 25 \)
First, calculate \( -\frac{7}{2} \times (-10) = 35 \), then \( 35 - 25 = 10 \). So when \( x = -10 \), \( y = 10 \).
Step2: Substitute \( x = -8 \) into the equation
Substitute \( x = -8 \) into \( y = -\frac{7}{2}x - 25 \):
\( y = -\frac{7}{2} \times (-8) - 25 \)
Calculate \( -\frac{7}{2} \times (-8) = 28 \), then \( 28 - 25 = 3 \). So when \( x = -8 \), \( y = 3 \).
Step3: Substitute \( x = -6 \) into the equation
Substitute \( x = -6 \) into \( y = -\frac{7}{2}x - 25 \):
\( y = -\frac{7}{2} \times (-6) - 25 \)
Calculate \( -\frac{7}{2} \times (-6) = 21 \), then \( 21 - 25 = -4 \). So when \( x = -6 \), \( y = -4 \).
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When \( x = -10 \), \( y = 10 \); when \( x = -8 \), \( y = 3 \); when \( x = -6 \), \( y = -4 \). So the filled table is:
| \( x \) | \( y \) |
|---|---|
| -8 | 3 |
| -6 | -4 |