Question

4
56
× 2
392
+ 1,1 0
1,512

Explanation:

Step1: Find the units digit of multiplier

We know \(56 \times \text{units digit} = 392\). Calculate the units digit:
\(\text{Units digit} = \frac{392}{56} = 7\)
So the multiplier is \(27\).

Step2: Find the missing tens digit

Calculate \(56 \times 20 = 1120\). This means the missing digit in \(1,1\square0\) is 2.

Step3: Verify the final sum

Check \(392 + 1120 = 1512\), which matches the total. The top small digit is the carryover from \(56 \times 7\): \(56 \times 7 = 392\), the carryover to the tens place is 3? No, wait, the small 4 above 5 is actually the carryover from the tens multiplication? No, correction: When calculating \(56 \times 7\), \(6 \times 7 = 42\), carryover 4 to the tens place, which is the small 4 above 5.

Answer:

The missing digits (top to bottom) are 4, 7, 2.

• Top small square: 4
• Square in multiplier: 7
• Square in 1,1□0: 2