Question

y = \frac{1}{3}x\
\

x	y	\
-9	\square	\
-3	\square	\
0	\square	\
3	\square	\
9	\square

Explanation:

Step1: Substitute \( x = -9 \) into \( y = \frac{1}{3}x \)

\( y = \frac{1}{3} \times (-9) = -3 \)

Step2: Substitute \( x = -3 \) into \( y = \frac{1}{3}x \)

\( y = \frac{1}{3} \times (-3) = -1 \)

Step3: Substitute \( x = 0 \) into \( y = \frac{1}{3}x \)

\( y = \frac{1}{3} \times 0 = 0 \)

Step4: Substitute \( x = 3 \) into \( y = \frac{1}{3}x \)

\( y = \frac{1}{3} \times 3 = 1 \)

Step5: Substitute \( x = 9 \) into \( y = \frac{1}{3}x \)

\( y = \frac{1}{3} \times 9 = 3 \)

Answer:

For \( x = -9 \), \( y = -3 \); for \( x = -3 \), \( y = -1 \); for \( x = 0 \), \( y = 0 \); for \( x = 3 \), \( y = 1 \); for \( x = 9 \), \( y = 3 \)

Filling the table:

\( x \)	\( y \)
-3	-1
0	0
3	1
9	3