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adding and subtracting fractions (unlike denominators) 1. \\(\\frac{4}{…

Question

adding and subtracting fractions
(unlike denominators)

  1. \\(\frac{4}{5} + \frac{1}{2} - \frac{3}{4} =\\) \t\t2. \\(\frac{25}{18} - \frac{2}{9} - \frac{1}{6} =\\)
  1. \\(\frac{2}{3} - \frac{5}{9} + \frac{11}{12} =\\) \t\t4. \\(\frac{42}{85} + \frac{10}{17} - \frac{2}{5} =\\)
  1. \\(\frac{3}{7} - \frac{1}{10} - \frac{1}{5} =\\) \t\t6. \\(\frac{5}{6} - \frac{25}{42} + \frac{4}{7} =\\)
  1. \\(\frac{12}{25} + \frac{8}{15} - \frac{3}{5} =\\) \t\t8. \\(\frac{1}{2} + \frac{2}{3} - \frac{3}{4} =\\)
  1. \\(\frac{3}{8} + \frac{5}{6} + \frac{7}{12} =\\) \t\t10. \\(\frac{12}{20} + \frac{3}{10} - \frac{2}{5} =\\)
  1. \\(\frac{20}{50} + \frac{10}{25} - \frac{55}{100} =\\) \t\t12. \\(\frac{40}{99} + \frac{4}{11} + \frac{2}{9} =\\)

Explanation:

Response
Problem 1: $\boldsymbol{\frac{4}{5} + \frac{1}{2} - \frac{3}{4}}$

Step 1: Find the least common denominator (LCD) of 5, 2, and 4.

The LCD of 5, 2, and 4 is 20.

Step 2: Rewrite each fraction with the LCD.

$\frac{4}{5} = \frac{4 \times 4}{5 \times 4} = \frac{16}{20}$, $\frac{1}{2} = \frac{1 \times 10}{2 \times 10} = \frac{10}{20}$, $\frac{3}{4} = \frac{3 \times 5}{4 \times 5} = \frac{15}{20}$

Step 3: Perform the operations.

$\frac{16}{20} + \frac{10}{20} - \frac{15}{20} = \frac{16 + 10 - 15}{20} = \frac{11}{20}$

Step 1: Find the LCD of 18, 9, and 6.

The LCD of 18, 9, and 6 is 18.

Step 2: Rewrite each fraction with the LCD.

$\frac{2}{9} = \frac{2 \times 2}{9 \times 2} = \frac{4}{18}$, $\frac{1}{6} = \frac{1 \times 3}{6 \times 3} = \frac{3}{18}$

Step 3: Perform the operations.

$\frac{25}{18} - \frac{4}{18} - \frac{3}{18} = \frac{25 - 4 - 3}{18} = \frac{18}{18} = 1$

Step 1: Find the LCD of 3, 9, and 12.

The LCD of 3, 9, and 12 is 36.

Step 2: Rewrite each fraction with the LCD.

$\frac{2}{3} = \frac{2 \times 12}{3 \times 12} = \frac{24}{36}$, $\frac{5}{9} = \frac{5 \times 4}{9 \times 4} = \frac{20}{36}$, $\frac{11}{12} = \frac{11 \times 3}{12 \times 3} = \frac{33}{36}$

Step 3: Perform the operations.

$\frac{24}{36} - \frac{20}{36} + \frac{33}{36} = \frac{24 - 20 + 33}{36} = \frac{37}{36} = 1\frac{1}{36}$

Answer:

$\frac{11}{20}$

Problem 2: $\boldsymbol{\frac{25}{18} - \frac{2}{9} - \frac{1}{6}}$