QUESTION IMAGE
Question
charter school
name
date
tables, equations, and graphs
- given the table. write the equation. graph it!
initial value (start) =
rate of change =
( y = )
| ( x ) | ( y ) |
|---|---|
| 1 | 1 |
| 2 | 4 |
| 3 | 7 |
- given the graph. write the equation.
slope =
( y )-intercept =
( y = )
- given the equation. fill in the table.
( y = 5x - 12 )
| ( x ) | ( y ) |
|---|---|
| -1 | |
| 0 | |
| 1 | |
| 2 | |
| 3 | |
| 20 |
slope (rate of change)
- find the slope
| time (seconds) | profit (dollars) |
|---|---|
| 9 | 25 |
| 12 | 29 |
( m = )
- find the slope, ( x )-intercept, and ( y )-intercept.
( m = )
( b = )
- find the slope of the line that contains the points:
( (-12, 8) ) and ( (-21, -20) )
- bob has saved 32 gummi bears. his mom gives him 3 gummis every 2 days.
what is the rate of change?
Step1: Find initial value (y-intercept)
Initial value is $y$ when $x=0$: $b=-2$
Step2: Calculate rate of change (slope)
Slope formula: $m=\frac{y_2-y_1}{x_2-x_1}=\frac{1-(-2)}{1-0}=3$
Step3: Write linear equation
$y=mx+b$ → $y=3x-2$
---
Step1: Identify slope from graph
Use two points $(-4,8)$ and $(0,2)$: $m=\frac{2-8}{0-(-4)}=\frac{-6}{4}=-\frac{3}{2}$
Step2: Find y-intercept
y-intercept is $y$ at $x=0$: $b=2$
Step3: Write linear equation
$y=mx+b$ → $y=-\frac{3}{2}x+2$
---
Step1: Substitute $x=-2$ into equation
$y=5(-2)-12=-10-12=-22$
Step2: Substitute $x=-1$ into equation
$y=5(-1)-12=-5-12=-17$
Step3: Substitute $x=0$ into equation
$y=5(0)-12=0-12=-12$
Step4: Substitute $x=1$ into equation
$y=5(1)-12=5-12=-7$
Step5: Substitute $x=2$ into equation
$y=5(2)-12=10-12=-2$
Step6: Substitute $x=3$ into equation
$y=5(3)-12=15-12=3$
Step7: Substitute $x=20$ into equation
$y=5(20)-12=100-12=88$
---
Step1: Calculate slope from table
$m=\frac{25-21}{9-6}=\frac{4}{3}$
---
Step1: Calculate slope from graph
Use two points $(0,-3)$ and $(2,0)$: $m=\frac{0-(-3)}{2-0}=\frac{3}{2}$
Step2: Find y-intercept
y-intercept is $y$ at $x=0$: $b=-3$
Step3: Find x-intercept
Set $y=0$: $0=\frac{3}{2}x-3$ → $\frac{3}{2}x=3$ → $x=2$
---
Step1: Calculate slope with two points
Slope formula: $m=\frac{y_2-y_1}{x_2-x_1}=\frac{-20-8}{-21-(-12)}=\frac{-28}{-9}=\frac{28}{9}$
---
Step1: Identify rate of change
Rate is gummis per day: $\frac{3}{2}=1.5$
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- Initial value (start) = $\boldsymbol{-2}$; Rate of Change = $\boldsymbol{3}$; $y=\boldsymbol{3x-2}$
(Graph: Plot points $(0,-2),(1,1),(2,4),(3,7)$ and draw a straight line through them)
- slope = $\boldsymbol{-\frac{3}{2}}$; y-intercept = $\boldsymbol{2}$; $y=\boldsymbol{-\frac{3}{2}x+2}$
3.
| $x$ | $y$ |
|---|---|
| -1 | -17 |
| 0 | -12 |
| 1 | -7 |
| 2 | -2 |
| 3 | 3 |
| 20 | 88 |
- $m=\boldsymbol{\frac{4}{3}}$
- $m=\boldsymbol{\frac{3}{2}}$; x-intercept = $\boldsymbol{2}$; y-intercept ($b$) = $\boldsymbol{-3}$
- $m=\boldsymbol{\frac{28}{9}}$
- Rate of change = $\boldsymbol{\frac{3}{2}}$ (or 1.5) gummi bears per day