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charter school name date tables, equations, and graphs 1. given the tab…

Question

charter school
name
date
tables, equations, and graphs

  1. given the table. write the equation. graph it!

initial value (start) =
rate of change =
( y = )

( x )( y )
11
24
37
  1. given the graph. write the equation.

slope =
( y )-intercept =
( y = )

  1. given the equation. fill in the table.

( y = 5x - 12 )

( x )( y )
-1
0
1
2
3
20

slope (rate of change)

  1. find the slope
time (seconds)profit (dollars)
925
1229

( m = )

  1. find the slope, ( x )-intercept, and ( y )-intercept.

( m = )
( b = )

  1. find the slope of the line that contains the points:

( (-12, 8) ) and ( (-21, -20) )

  1. bob has saved 32 gummi bears. his mom gives him 3 gummis every 2 days.

what is the rate of change?

Explanation:

Step1: Find initial value (y-intercept)

Initial value is $y$ when $x=0$: $b=-2$

Step2: Calculate rate of change (slope)

Slope formula: $m=\frac{y_2-y_1}{x_2-x_1}=\frac{1-(-2)}{1-0}=3$

Step3: Write linear equation

$y=mx+b$ → $y=3x-2$
---

Step1: Identify slope from graph

Use two points $(-4,8)$ and $(0,2)$: $m=\frac{2-8}{0-(-4)}=\frac{-6}{4}=-\frac{3}{2}$

Step2: Find y-intercept

y-intercept is $y$ at $x=0$: $b=2$

Step3: Write linear equation

$y=mx+b$ → $y=-\frac{3}{2}x+2$
---

Step1: Substitute $x=-2$ into equation

$y=5(-2)-12=-10-12=-22$

Step2: Substitute $x=-1$ into equation

$y=5(-1)-12=-5-12=-17$

Step3: Substitute $x=0$ into equation

$y=5(0)-12=0-12=-12$

Step4: Substitute $x=1$ into equation

$y=5(1)-12=5-12=-7$

Step5: Substitute $x=2$ into equation

$y=5(2)-12=10-12=-2$

Step6: Substitute $x=3$ into equation

$y=5(3)-12=15-12=3$

Step7: Substitute $x=20$ into equation

$y=5(20)-12=100-12=88$
---

Step1: Calculate slope from table

$m=\frac{25-21}{9-6}=\frac{4}{3}$
---

Step1: Calculate slope from graph

Use two points $(0,-3)$ and $(2,0)$: $m=\frac{0-(-3)}{2-0}=\frac{3}{2}$

Step2: Find y-intercept

y-intercept is $y$ at $x=0$: $b=-3$

Step3: Find x-intercept

Set $y=0$: $0=\frac{3}{2}x-3$ → $\frac{3}{2}x=3$ → $x=2$
---

Step1: Calculate slope with two points

Slope formula: $m=\frac{y_2-y_1}{x_2-x_1}=\frac{-20-8}{-21-(-12)}=\frac{-28}{-9}=\frac{28}{9}$
---

Step1: Identify rate of change

Rate is gummis per day: $\frac{3}{2}=1.5$

Answer:

  1. Initial value (start) = $\boldsymbol{-2}$; Rate of Change = $\boldsymbol{3}$; $y=\boldsymbol{3x-2}$

(Graph: Plot points $(0,-2),(1,1),(2,4),(3,7)$ and draw a straight line through them)

  1. slope = $\boldsymbol{-\frac{3}{2}}$; y-intercept = $\boldsymbol{2}$; $y=\boldsymbol{-\frac{3}{2}x+2}$

3.

$x$$y$
-1-17
0-12
1-7
2-2
33
2088
  1. $m=\boldsymbol{\frac{4}{3}}$
  2. $m=\boldsymbol{\frac{3}{2}}$; x-intercept = $\boldsymbol{2}$; y-intercept ($b$) = $\boldsymbol{-3}$
  3. $m=\boldsymbol{\frac{28}{9}}$
  4. Rate of change = $\boldsymbol{\frac{3}{2}}$ (or 1.5) gummi bears per day