Question

choose the sum that is greater than 5. $4\frac{1}{8} + \frac{5}{8}$ $4\frac{3}{8} + \frac{3}{8}$ $4\frac{5}{8} + \frac{7}{8}$ $4\frac{6}{8} + \frac{1}{8}$

Explanation:

Step1: Calculate \( 4\frac{1}{8}+\frac{5}{8} \)

First, convert the mixed number to an improper fraction or add the fractions directly. \( 4\frac{1}{8}+\frac{5}{8}=4+\frac{1 + 5}{8}=4+\frac{6}{8}=4\frac{3}{4}=4.75 \), which is less than 5.

Step2: Calculate \( 4\frac{3}{8}+\frac{3}{8} \)

\( 4\frac{3}{8}+\frac{3}{8}=4+\frac{3+3}{8}=4+\frac{6}{8}=4\frac{3}{4}=4.75 \), less than 5.

Step3: Calculate \( 4\frac{5}{8}+\frac{7}{8} \)

\( 4\frac{5}{8}+\frac{7}{8}=4+\frac{5 + 7}{8}=4+\frac{12}{8}=4 + 1\frac{4}{8}=5\frac{1}{2}=5.5 \), which is greater than 5.

Step4: Calculate \( 4\frac{6}{8}+\frac{1}{8} \)

\( 4\frac{6}{8}+\frac{1}{8}=4+\frac{6+1}{8}=4+\frac{7}{8}=4\frac{7}{8}=4.875 \), less than 5.

Answer:

\( 4\frac{5}{8}+\frac{7}{8} \)