Question

class examples: write the slope - intercept form of the equation of each line. (y = mx + b)
1)
2)

Explanation:

Step1: Analyze vertical line (1)

A vertical line has an undefined slope and the form $x = c$, where $c$ is the x-intercept. From the graph, the line crosses the x-axis at $x=2$. Vertical lines cannot be written in $y=mx+b$ (slope-intercept) form because they have no defined slope and no y-intercept (unless it's the y-axis itself, which this is not).

Step2: Identify slope for line (2)

Use slope formula $m=\frac{y_2-y_1}{x_2-x_1}$. Pick two points, e.g., $(0,-2)$ and $(2,1)$.
$m=\frac{1-(-2)}{2-0}=\frac{3}{2}$

Step3: Find y-intercept for line (2)

The line crosses the y-axis at $(0,-2)$, so $b=-2$.

Step4: Write slope-intercept form for line (2)

Substitute $m=\frac{3}{2}$ and $b=-2$ into $y=mx+b$.
$y=\frac{3}{2}x - 2$

Answer:

1. This vertical line cannot be written in slope-intercept ($y=mx+b$) form. Its equation is $x=2$.
2. $y=\frac{3}{2}x - 2$