QUESTION IMAGE
Question
complete the table of values for the functions ( f(x) = |2x| ) and ( g(x) = 3^{x + 2} ).
write your answers as whole numbers, decimals, or simplified fractions or mixed numbers.
| ( x ) | ( f(x) ) | ( g(x) ) |
|---|---|---|
| ( -3 ) | ||
| ( -2 ) | ||
| ( -1 ) | ||
| ( 0 ) |
based on the values in the table, where does the equation ( f(x) = g(x) ) have a solution?
between ( x = -3 ) and ( x = -2 ) ( x = -2 )
between ( x = -2 ) and ( x = -1 ) ( x = -1 )
Part 1: Completing the table for \( f(x) = |2x| \) and \( g(x) = 3^{x + 2} \)
For \( f(x) = |2x| \):
- Step 1: When \( x = -4 \)
Substitute \( x = -4 \) into \( f(x) \):
\( f(-4) = |2(-4)| = |-8| = 8 \)
- Step 2: When \( x = -3 \)
Substitute \( x = -3 \):
\( f(-3) = |2(-3)| = |-6| = 6 \)
- Step 3: When \( x = -2 \)
Substitute \( x = -2 \):
\( f(-2) = |2(-2)| = |-4| = 4 \)
- Step 4: When \( x = -1 \)
Substitute \( x = -1 \):
\( f(-1) = |2(-1)| = |-2| = 2 \)
- Step 5: When \( x = 0 \)
Substitute \( x = 0 \):
\( f(0) = |2(0)| = |0| = 0 \)
For \( g(x) = 3^{x + 2} \):
- Step 1: When \( x = -4 \)
Substitute \( x = -4 \):
\( g(-4) = 3^{-4 + 2} = 3^{-2} = \frac{1}{3^2} = \frac{1}{9} \approx 0.111 \)
- Step 2: When \( x = -3 \)
Substitute \( x = -3 \):
\( g(-3) = 3^{-3 + 2} = 3^{-1} = \frac{1}{3} \approx 0.333 \)
- Step 3: When \( x = -2 \)
Substitute \( x = -2 \):
\( g(-2) = 3^{-2 + 2} = 3^{0} = 1 \)
- Step 4: When \( x = -1 \)
Substitute \( x = -1 \):
\( g(-1) = 3^{-1 + 2} = 3^{1} = 3 \)
- Step 5: When \( x = 0 \)
Substitute \( x = 0 \):
\( g(0) = 3^{0 + 2} = 3^{2} = 9 \)
Part 2: Finding where \( f(x) = g(x) \)
We analyze the values of \( f(x) \) and \( g(x) \) at each \( x \):
| \( x \) | \( f(x) \) | \( g(x) \) | Relationship |
|---|---|---|---|
| \( -3 \) | \( 6 \) | \( \frac{1}{3} \approx 0.333 \) | \( f(x) > g(x) \) |
| \( -2 \) | \( 4 \) | \( 1 \) | \( f(x) > g(x) \) |
| \( -1 \) | \( 2 \) | \( 3 \) | \( f(x) < g(x) \) |
At \( x = -2 \), \( f(-2) = 4 \) and \( g(-2) = 1 \) (so \( f > g \)).
At \( x = -1 \), \( f(-1) = 2 \) and \( g(-1) = 3 \) (so \( f < g \)).
Since \( f(x) \) is decreasing (or constant) and \( g(x) \) is increasing, the solution to \( f(x) = g(x) \) lies between \( x = -2 \) and \( x = -1 \) (because \( f(x) \) crosses from above \( g(x) \) to below \( g(x) \) in this interval).
Final Table:
| \( x \) | \( f(x) \) | \( g(x) \) |
|---|---|---|
| \( -3 \) | \( 6 \) | \( \frac{1}{3} \) (or \( 0.333 \)) |
| \( -2 \) | \( 4 \) | \( 1 \) |
| \( -1 \) | \( 2 \) | \( 3 \) |
| \( 0 \) | \( 0 \) | \( 9 \) |
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to \( f(x) = g(x) \):
between \( x = -2 \) and \( x = -1 \)