Question

complete the table to vertically stretch the parent function $f(x)=x^3$ by a factor of 3. (2 poi
this table represents a
function of the form y,
where the coefficient is
missing and needs to
be determined to
complete the values for
y at given x values.

$x$

$y=kf(x)=\square x^3$

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0

0

1

$\square$

2

$\square$

Explanation:

Step1: Identify vertical stretch factor

A vertical stretch by factor 3 means $k=3$, so the function is $y=3x^3$.

Step2: Calculate y when x=1

Substitute $x=1$ into $y=3x^3$.
$y=3(1)^3=3(1)=3$

Step3: Calculate y when x=2

Substitute $x=2$ into $y=3x^3$.
$y=3(2)^3=3(8)=24$

Answer:

The completed table values are:

• Missing coefficient: $3$
• $y$ when $x=1$: $3$
• $y$ when $x=2$: $24$

Filled table:

$x$	$y=3x^3$
1	3
2	24