Question

5
consider this function
$f(x) = x(12 - x)$
what are the values of $f(0)$, $f(5)$ and $f(12)$?
$f(0) = \square$
$f(5) = \square$
$f(12) = \square$

Explanation:

Step1: Calculate \( f(0) \)

Substitute \( x = 0 \) into \( f(x)=x(12 - x) \).
\( f(0)=0\times(12 - 0) = 0\times12 = 0 \)

Step2: Calculate \( f(5) \)

Substitute \( x = 5 \) into \( f(x)=x(12 - x) \).
\( f(5)=5\times(12 - 5)=5\times7 = 35 \)

Step3: Calculate \( f(12) \)

Substitute \( x = 12 \) into \( f(x)=x(12 - x) \).
\( f(12)=12\times(12 - 12)=12\times0 = 0 \)

Answer:

\( f(0)=\boldsymbol{0} \)
\( f(5)=\boldsymbol{35} \)
\( f(12)=\boldsymbol{0} \)