Question

d103b
(9) \\( 91 \overline{) 190} \\)
(13) \\( 92 \overline{) 190} \\)
(10) \\( 91 \overline{) 276} \\)
(14) \\( 92 \overline{) 276} \\)
(11) \\( 91 \overline{) 465} \\)
(15) \\( 92 \overline{) 465} \\)
(12) \\( 91 \overline{) 728} \\)
(16) \\( 92 \overline{) 728} \\)

Explanation:

Step1: Divide 190 by 91

$190 \div 91 = 2$ remainder $8$, so $190 = 91\times2 + 8$

Step2: Divide 190 by 92

$190 \div 92 = 2$ remainder $6$, so $190 = 92\times2 + 6$

Step3: Divide 276 by 91

$276 \div 91 = 3$ remainder $3$, so $276 = 91\times3 + 3$

Step4: Divide 276 by 92

$276 \div 92 = 3$ remainder $0$, so $276 = 92\times3 + 0$

Step5: Divide 465 by 91

$465 \div 91 = 5$ remainder $10$, so $465 = 91\times5 + 10$

Step6: Divide 465 by 92

$465 \div 92 = 5$ remainder $5$, so $465 = 92\times5 + 5$

Step7: Divide 728 by 91

$728 \div 91 = 8$ remainder $0$, so $728 = 91\times8 + 0$

Step8: Divide 728 by 92

$728 \div 92 = 7$ remainder $84$, so $728 = 92\times7 + 84$

Answer:

(9) $190\div91=2$ remainder $8$
(13) $190\div92=2$ remainder $6$
(10) $276\div91=3$ remainder $3$
(14) $276\div92=3$ remainder $0$
(11) $465\div91=5$ remainder $10$
(15) $465\div92=5$ remainder $5$
(12) $728\div91=8$ remainder $0$
(16) $728\div92=7$ remainder $84$