differentiate. y = 18\\sqrt{x} \\frac{d}{dx}(18\\sqrt{x}) = \\square

$differentiate. y = 18\\sqrt{x} \\frac{d}{dx}(18\\sqrt{x}) = \\square$

differentiate. y = 18\sqrt{x}
\frac{d}{dx}(18\sqrt{x}) = \square

$y = 18x^{\frac{1}{2}}$

$\frac{d}{dx}(ax^n)=anx^{n - 1}$, so $\frac{d}{dx}(18x^{\frac{1}{2}})=18\times\frac{1}{2}x^{\frac{1}{2}-1}$

$9x^{-\frac{1}{2}}=\frac{9}{\sqrt{x}}$

$\frac{9}{\sqrt{x}}$