Question

differentiate.
y = 3x^3 - 10x^2 + 12x + 4
\frac{dy}{dx}=square

Explanation:

Step1: Apply power - rule to each term

$\frac{d}{dx}(3x^{3})=3\times3x^{2}=9x^{2}$, $\frac{d}{dx}(- 10x^{2})=-10\times2x=-20x$, $\frac{d}{dx}(12x)=12$, $\frac{d}{dx}(4)=0$

Step2: Sum up the derivatives

$y' = 9x^{2}-20x + 12$

Answer:

$9x^{2}-20x + 12$