Question

differentiate. y = 4x^3 - 8x^2 + 16x + 3
\frac{dy}{dx}=square

Explanation:

Step1: Apply power - rule

$\frac{d}{dx}(4x^{3})=4\times3x^{2}=12x^{2}$, $\frac{d}{dx}(- 8x^{2})=-8\times2x=-16x$, $\frac{d}{dx}(16x)=16$, $\frac{d}{dx}(3)=0$

Step2: Sum up derivatives

$\frac{dy}{dx}=12x^{2}-16x + 16$

Answer:

$12x^{2}-16x + 16$