Question

(c) $h(t) = \frac{1}{\sqrt3{t - 5}}$ the domain in interval notation is \boxed{}.

Explanation:

Step1: Identify denominator constraint

The denominator $\sqrt[3]{t-5}$ cannot equal 0.
$\sqrt[3]{t-5}
eq 0$

Step2: Solve for t from denominator

Set $t-5
eq 0$, so $t
eq 5$.

Step3: Check cube root domain

Cube roots accept all real numbers, so no other restrictions.

Answer:

$(-\infty,5) \cup (5,\infty)$