Question

drag and drop the code statement that assigns cond_str with a conditional expression that evaluates to string
egative\ if user_val is less than 0, and
on - negative\ otherwise. then, the program outputs user_val followed by \ is \ and cond_str. ex. if the input is -9, then the output is: -9 is negative. note: only one code statement on the left should be used in the final solution. how to use this tool unused
on - negative\ if user_val < 0 else
egative\ cond_str =
on - negative\ if user_val < 0 else
egative\ cond_str =
egative\ if user_val > 0 else
on - negative\ cond_str =
egative\ if user_val < 0 else
on - negative\ main.py user_val = int(input()) print(f\{user_val} is {cond_str}.\) load default templates... check feedback?

Explanation:

Step1: Match logic to requirement

We need cond_str to be "negative" when user_val < 0, else "non-negative". The correct conditional expression is:

cond_str = "negative" if user_val < 0 else "non-negative"

Step2: Insert into code structure

Place the expression between the input and print lines in main.py:

user_val = int(input())
cond_str = "negative" if user_val < 0 else "non-negative"
print(f"{user_val} is {cond_str}.")

Answer:

The completed code is:

user_val = int(input())
cond_str = "negative" if user_val < 0 else "non-negative"
print(f"{user_val} is {cond_str}.")

For input -9, the output will be: -9 is negative.