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5. draw a graph of the function. then determine which of the following …

Question

  1. draw a graph of the function. then determine which of the following statements are true:

$y = \sqrt{x + 4} - 1$

  • there is an y - intercept at $y = - 1$
  • there is an x - intercept at $x = 1$
  • there is an y - intercept at $y = 1$
  • there is an x - intercept at $x = - 4$
  • there is an x - intercept at $x = - 3$
  • there is an y - intercept at $y = 1.5$

show your work

Explanation:

Step1: Find y - intercept (set x = 0)

To find the y - intercept, we substitute \(x = 0\) into the function \(y=\sqrt{x + 4}-1\).
\[y=\sqrt{0 + 4}-1=\sqrt{4}-1 = 2-1=1\] Wait, no, wait. Wait, \(\sqrt{4}=2\), so \(y = 2 - 1=1\)? Wait, no, let's recalculate. Wait, \(x = 0\), so \(y=\sqrt{0 + 4}-1=\sqrt{4}-1=2 - 1 = 1\)? Wait, but let's check again. Wait, maybe I made a mistake. Wait, no, \(\sqrt{4}=2\), so \(2-1 = 1\). Wait, but let's check the x - intercept (set y = 0).

Step2: Find x - intercept (set y = 0)

Set \(y = 0\) in \(y=\sqrt{x + 4}-1\). Then:
\[0=\sqrt{x + 4}-1\]
Add 1 to both sides:
\[\sqrt{x + 4}=1\]
Square both sides:
\[x + 4=1\]
Subtract 4 from both sides:
\[x=1 - 4=-3\]

Wait, now let's re - check the y - intercept. When \(x = 0\), \(y=\sqrt{0 + 4}-1=\sqrt{4}-1 = 2-1 = 1\). Wait, but the first option says "There is an y - intercept at \(y=-1\)". That's wrong. Wait, maybe I made a mistake in the y - intercept calculation. Wait, no, \(\sqrt{4}=2\), \(2-1 = 1\). So the y - intercept is at \(y = 1\)? But the third option says "There is an y - intercept at \(y = 1\)". Wait, but let's check the x - intercept again. When \(y = 0\), we have \(\sqrt{x + 4}=1\), so \(x+4 = 1\), \(x=-3\). So the x - intercept is at \(x=-3\).

Wait, let's re - do the y - intercept:

For y - intercept, \(x = 0\):

\(y=\sqrt{0 + 4}-1=\sqrt{4}-1=2 - 1 = 1\). So the y - intercept is at \(y = 1\) (so the third option "There is an y - intercept at \(y = 1\)" is correct? Wait, but the first option says \(y=-1\), which is wrong. Wait, maybe I messed up. Wait, no, \(\sqrt{4}=2\), \(2-1 = 1\). So y - intercept is \(y = 1\) (when \(x = 0\), \(y = 1\)).

For x - intercept, \(y = 0\):

\(0=\sqrt{x + 4}-1\)

\(\sqrt{x + 4}=1\)

\(x + 4=1\)

\(x=-3\). So the x - intercept is at \(x=-3\) (the fifth option "There is an x - intercept at \(x=-3\)" is correct).

Wait, let's check the first option: "There is an y - intercept at \(y=-1\)". When \(x = 0\), \(y = 1\), so that's wrong. The third option: "There is an y - intercept at \(y = 1\)" is correct? Wait, but let's check again.

Wait, maybe I made a mistake in the y - intercept. Wait, \(\sqrt{4}=2\), \(2-1 = 1\). So yes, \(y = 1\) when \(x = 0\). So the third option is correct. And the fifth option (x - intercept at \(x=-3\)) is correct.

Wait, let's check the other options:

  • "There is an x - intercept at \(x = 1\)": When \(x = 1\), \(y=\sqrt{1 + 4}-1=\sqrt{5}-1\approx2.24 - 1 = 1.24

eq0\), so wrong.

  • "There is an x - intercept at \(x=-4\)": When \(x=-4\), \(y=\sqrt{-4 + 4}-1=\sqrt{0}-1=-1

eq0\), so wrong.

  • "There is an y - intercept at \(y=-1\)": When \(x = 0\), \(y = 1

eq-1\), wrong.

  • "There is an y - intercept at \(y = 1.5\)": When \(x = 0\), \(y = 1

eq1.5\), wrong.

  • "There is an x - intercept at \(x=-3\)": Correct, as we found \(x=-3\) when \(y = 0\).
  • "There is an y - intercept at \(y = 1\)": Correct, as when \(x = 0\), \(y = 1\). Wait, but the third option is "There is an y - intercept at \(y = 1\)" and the fifth option is "There is an x - intercept at \(x=-3\)".

Wait, let's re - check the y - intercept calculation:

\(x = 0\), so \(y=\sqrt{0 + 4}-1=\sqrt{4}-1 = 2-1 = 1\). So the y - intercept is at \(y = 1\) (so the third option is correct). The x - intercept: when \(y = 0\), \(0=\sqrt{x + 4}-1\Rightarrow\sqrt{x + 4}=1\Rightarrow x + 4 = 1\Rightarrow x=-3\) (so the fifth option is correct).

Wait, but the first option says "There is an y - intercept at \(y=-1\)": wrong. The second option "There is an x - intercept at \(x = 1\)": wrong. The fourth option "There is an x - intercept at \(x=-4\)":…

Answer:

  • There is an y - intercept at \(y = 1\) (the option: There is an y - intercept at \(y = 1\))
  • There is an x - intercept at \(x=-3\) (the option: There is an x - intercept at \(x=-3\))

In boxed form (for the correct options):

C. There is an y - intercept at \(y = 1\)

E. There is an x - intercept at \(x=-3\)