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evaluate the function for the given values of x. $f(x) = \\begin{cases}…

Question

evaluate the function for the given values of x.
$f(x) = \

$$\begin{cases} -5x + 7 & \\text{for } x < -1 \\\\ x^2 + 2 & \\text{for } -1 \\leq x < 5 \\\\ 6 & \\text{for } x \\geq 5 \\end{cases}$$

$
part 1 of 5
$f(0) = \square$
part 2 of 5
$f(-2) = \square$

Explanation:

Step1: Match x=0 to function rule

Since $-1 \leq 0 < 5$, use $f(x)=x^2+2$.

Step2: Calculate f(0)

$f(0)=0^2+2=0+2=2$

Step3: Match x=-2 to function rule

Since $-2 < -1$, use $f(x)=-5x+7$.

Step4: Calculate f(-2)

$f(-2)=-5(-2)+7=10+7=17$

Answer:

$f(0)=2$
$f(-2)=17$