Question

evaluate the function $f(r)=\sqrt{r + 2}-8$ at the given values of the independent variable and simplify.\
a. $f(-2)$ \
b. $f(34)$ \
c. $f(x - 2)$\
\
a. $f(-2)=\square$ (simplify your answer.)\
b. $f(34)=\square$ (simplify your answer.)\
c. $f(x - 2)=\square$ (simplify your answer.)

Explanation:

Step1: Substitute $r=-2$

$f(-2)=\sqrt{-2+2}-8$

Step2: Simplify the radical

$f(-2)=\sqrt{0}-8=0-8$

Step3: Substitute $r=34$

$f(34)=\sqrt{34+2}-8$

Step4: Simplify the radical

$f(34)=\sqrt{36}-8=6-8$

Step5: Substitute $r=x-2$

$f(x-2)=\sqrt{(x-2)+2}-8$

Step6: Simplify the radical

$f(x-2)=\sqrt{x}-8$

Answer:

a. $f(-2)=-8$
b. $f(34)=-2$
c. $f(x-2)=\sqrt{x}-8$