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Question
evaluate logarithms (level 3) unique id: 0062
score: 1/4 penalty: 0.25 off
question
evaluate:
\log_{128} 2
Step1: Recall logarithm definition
Let \( \log_{128} 2 = x \). By definition of logarithm, this means \( 128^x = 2 \).
Step2: Express 128 as power of 2
We know that \( 128 = 2^7 \), so substitute into the equation: \( (2^7)^x = 2 \).
Step3: Simplify left side
Using exponent rule \( (a^m)^n = a^{mn} \), we get \( 2^{7x} = 2^1 \).
Step4: Equate exponents
Since the bases are equal, the exponents must be equal: \( 7x = 1 \).
Step5: Solve for x
Divide both sides by 7: \( x = \frac{1}{7} \).
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\(\frac{1}{7}\)